3[4-(y+2)]=

Solution for 3[4-(y+2)]= equation:

Simplifying
3[4 + -1(y + 2)] = 0

Reorder the terms:
3[4 + -1(2 + y)] = 0
3[4 + (2 * -1 + y * -1)] = 0
3[4 + (-2 + -1y)] = 0

Combine like terms: 4 + -2 = 2
3[2 + -1y] = 0
[2 * 3 + -1y * 3] = 0
[6 + -3y] = 0

Solving
6 + -3y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -3y = 0 + -6

Combine like terms: 6 + -6 = 0
0 + -3y = 0 + -6
-3y = 0 + -6

Combine like terms: 0 + -6 = -6
-3y = -6

Divide each side by '-3'.
y = 2

Simplifying
y = 2